Q:

Two trains simultaneously left points M and N and headed towards each other. The distance between point M and point N is 380 mi. The speed of the train, which started, from point N was 5 mph faster than the speed of the other train. In two hours after the departure the distance between the trains was 30 mi. What is the speed of each train?

Accepted Solution

A:
Answer:speed of train from station M = 85miles per hourspeed of train from station N = 90miles per hourStep-by-step explanation:Given that,distance between two points M and N is 380 milesSuppose speed of trainM is xSo speed of trainN is 5 + xFormula to usedistance = speed x timefor the train from point Md = x * 2d = 2x for the train from point Nd = (5 + x) * 2 the above 2 distances plus 30 miles equals 380 milesEquation2x + 2(x+5) + 30 = 3802x + 2x + 10 + 30 = 3804x + 40 = 3804x = 380 - 404x = 340x = 340/4x = 85 mph for trainMput the value in second train's speedx + 5 85 + 5 = 90 mph for trainN